I enjoy the Project Euler problems. I've never asked for help even though I've struggeled
a lot at them. Even still I've only done ~10 in my preferred language, C++. I'm now learning a little C and I've decided that Project Euler would be a great place to practise what I've learned. So here's my solution to problem 1 in C:
#include <stdio.h>
int main(void)
{
int total=0;
int i=0;
while(i<1000)
{
if(i%3==0 || i%5==0)
total+=i;
i++;
}
printf("%d", total);
}
Execution time: 0.042 s
    That's all then. I'll post up my solutions to the other problems as I finish them. All comments welcome.
       NotMyFault
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ReplyDeleteThe correct answer is 233168. According to your source we will not get correct output using int data type. :) You can check at Project Euler site. I have a solution for it. I like your site. it is really helpful for us. thanks.
ReplyDeletevisit:
http://c-programming-practice.blogspot.com/2013/06/sum-of-all-multiples-of-3-or-5-below.html
but this is working for only a single test case (T)
ReplyDelete